What is the solution for y^{'''}+2y^{''}-5y^'-6y=0 ?

The solution for y^{'''}+2y^{''}-5y^'-6y=0 is y=c_{1}e^{-t}+c_{2}e^{2t}+c_{3}e^{-3t}

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y^{'''}+2y^{''}-5y^'-6y=0

y^{^{'''}} + 2 y^{^{''}} - 5 y^{^{'}} - 6 y = 0

y = c_{1} e^{- t} + c_{2} e^{2 t} + c_{3} e^{- 3 t}

Solution steps

y^{'''} (t) + 2 y^{''} (t) - 5 y^{'} (t) - 6 y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{2 t} + c_{3} e^{- 3 t}

y = c_{1} e^{- t} + c_{2} e^{2 t} + c_{3} e^{- 3 t}

\int_{0}^{π} 16 sin (x) d x

y^{^{''}} - y^{^{'}} + 20 y = 0

x \to 3 + lim (\frac{5}{x - 3})

(x - 2)^{6}

x \to 1 lim (3 x - 2)

What is the solution for y^{'''}+2y^{''}-5y^'-6y=0 ?
The solution for y^{'''}+2y^{''}-5y^'-6y=0 is y=c_{1}e^{-t}+c_{2}e^{2t}+c_{3}e^{-3t}