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Popular >

y^'=e^{5x+4y}

Solution

y^{^{'}} = e^{5 x + 4 y}

Solution

y = - \frac{ln ( - \frac{4}{5} e ^{5 x} - c _{1} )}{4}

Solution steps

y^{'} (x) = e^{5 x + 4 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{4}{5} e ^{5 x} - c _{1} )}{4}

y = - \frac{ln ( - \frac{4}{5} e ^{5 x} - c _{1} )}{4}

Popular Examples

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n = 0 \sum \infty \frac{1}{5}

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y = 3 x^{2} + 3 x - 5

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\int \frac{1}{4 ( x ^{2} + 1 )} d x

integral of cos(x)-5sin(x)

\int cos (x) - 5 sin (x) d x

derivative of 7sqrt(x)+3

\frac{d}{d x} (7 x + 3)

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{5x+4y} ?
The solution for y^'=e^{5x+4y} is y=-(ln(-4/5 e^{5x}-c_{1}))/4