What is the solution for xy^'+(x+1/3)y=e^{-2x}y^{-2} ?

The solution for xy^'+(x+1/3)y=e^{-2x}y^{-2} is y=\sqrt[3]{(3/(e^{2x)}+(c_{1})/(e^{3x)})/x}

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xy^'+(x+1/3)y=e^{-2x}y^{-2}

x y^{^{'}} + (x + \frac{1}{3}) y = e^{- 2 x} y^{- 2}

Solution steps

x y^{'} (x) + (x + \frac{1}{3}) y = e^{- 2 x} y^{- 2}

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What is the solution for xy^'+(x+1/3)y=e^{-2x}y^{-2} ?
The solution for xy^'+(x+1/3)y=e^{-2x}y^{-2} is y=\sqrt[3]{(3/(e^{2x)}+(c_{1})/(e^{3x)})/x}