What is the tangent of f(x)=x^2-4,(4,12) ?

The tangent of f(x)=x^2-4,(4,12) is y=8x-20

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tangent of f(x)=x^2-4,(4,12)

tangent of

f (x) = x^{2} - 4, (4, 12)

y = 8 x - 20

Solution steps

Find the slope of

f (x) = x^{2} - 4 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 4

(4, 12) : m = 8

Find the line with slope m=

8

and passing through

(4, 12) : y = 8 x - 20

y = 8 x - 20

\frac{d}{d x} (e^{(5 x)})

\int \frac{4 x + 6}{( x ^{2} + 2 ) ( x + 2 )} d x

(x + y) d x + (x + 2 y) d y = 0

\int_{2}^{6} \frac{1}{x - 2} d x

x \to \infty lim (ln (+ x))

What is the tangent of f(x)=x^2-4,(4,12) ?
The tangent of f(x)=x^2-4,(4,12) is y=8x-20