What is (\partial)/(\partial x)(-x+y+2) ?

The answer to (\partial)/(\partial x)(-x+y+2) is -1

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(\partial)/(\partial x)(-x+y+2)

\frac{\partial}{\partial x} (- x + y + 2)

- 1

Solution steps

\frac{\partial}{\partial x} (- x + y + 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (2) = 0

= - 1 + 0 + 0

Simplify

= - 1

\frac{d}{d x} (cos (4 x - \frac{π}{3}))

\int ln (5 x) d x

\int x^{2} e^{- \frac{x ^{2}}{2}} d x

x \to \frac{π}{2} lim (2 e^{x} cos (x))

y = 8 x^{5} + 10 x^{3} - 4

What is (\partial)/(\partial x)(-x+y+2) ?
The answer to (\partial)/(\partial x)(-x+y+2) is -1