What is the derivative of 4+3x-2x^3 ?

The derivative of 4+3x-2x^3 is -6x^2+3

What is the first derivative of 4+3x-2x^3 ?

The first derivative of 4+3x-2x^3 is -6x^2+3

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\frac{d}{d x} (4 + 3 x - 2 x^{3})

- 6 x^{2} + 3

Solution steps

\frac{d}{d x} (4 + 3 x - 2 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) + \frac{d}{d x} (3 x) - \frac{d}{d x} (2 x^{3})

\frac{d}{d x} (4) = 0

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= 0 + 3 - 6 x^{2}

Simplify

= - 6 x^{2} + 3

\frac{d}{d x} (\frac{12 x}{( x ^{2} + 2 ) ^{2}})

f (x) = ln (x^{2} + 4)

y^{^{'}} - 2 y = 0

\frac{d}{d x} (ln (arctan (2 x)))

x \to 0 + lim (x^{8 s i n (x)})

What is the derivative of 4+3x-2x^3 ?
The derivative of 4+3x-2x^3 is -6x^2+3
What is the first derivative of 4+3x-2x^3 ?
The first derivative of 4+3x-2x^3 is -6x^2+3