What is the integral of 1/(e^{6x)} ?

The integral of 1/(e^{6x)} is -1/6 e^{-6x}+C

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integral of 1/(e^{6x)}

\int \frac{1}{e ^{6 x}} d x

- \frac{1}{6} e^{- 6 x} + C

Solution steps

\int \frac{1}{e ^{6 x}} d x

Apply exponent rule:

\frac{1}{a ^{b}} = a^{- b}

\frac{1}{e ^{6 x}} = e^{- 6 x}

= \int e^{- 6 x} d x

Apply u-substitution

: \int - \frac{1}{6} e^{u} d u

= \int - \frac{1}{6} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{6} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - \frac{1}{6} e^{u}

Substitute back

u = - 6 x

= - \frac{1}{6} e^{- 6 x}

Add a constant to the solution

= - \frac{1}{6} e^{- 6 x} + C

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\frac{d}{d x} (\frac{e ^{x}}{e ^{x} - 1})

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What is the integral of 1/(e^{6x)} ?
The integral of 1/(e^{6x)} is -1/6 e^{-6x}+C