What is the integral of (cos(2t))/2 ?

The integral of (cos(2t))/2 is 1/4 sin(2t)+C

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integral of (cos(2t))/2

\int \frac{cos ( 2 t )}{2} d t

\frac{1}{4} sin (2 t) + C

Solution steps

\int \frac{cos ( 2 t )}{2} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int cos (2 t) d t

Apply u-substitution

: \int cos (u) \frac{1}{2} d u

= \frac{1}{2} \cdot \int cos (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{2} \cdot \frac{1}{2} sin (u)

Substitute back

u = 2 t

= \frac{1}{2} \cdot \frac{1}{2} sin (2 t)

Simplify

\frac{1}{2} \cdot \frac{1}{2} sin (2 t) : \frac{1}{4} sin (2 t)

= \frac{1}{4} sin (2 t)

Add a constant to the solution

= \frac{1}{4} sin (2 t) + C

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What is the integral of (cos(2t))/2 ?
The integral of (cos(2t))/2 is 1/4 sin(2t)+C