What is (\partial)/(\partial θ)(e^rcos(θ)) ?

The answer to (\partial)/(\partial θ)(e^rcos(θ)) is -e^rsin(θ)

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(\partial)/(\partial θ)(e^rcos(θ))

\frac{\partial}{\partial θ} (e^{r} cos (θ))

- e^{r} sin (θ)

Solution steps

\frac{\partial}{\partial θ} (e^{r} cos (θ))

Treat

r

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{r} \frac{\partial}{\partial θ} (cos (θ))

Apply the common derivative:

\frac{\partial}{\partial θ} (cos (θ)) = - sin (θ)

= e^{r} (- sin (θ))

Simplify

= - e^{r} sin (θ)

\int_{2}^{4} \frac{2}{x} - \frac{1}{8} x d x

y = - 8 x^{3} + 9 x^{2} + 6 x - 5

n = 0 \sum \infty \frac{3 ^{n}}{n ^{3}}

6 y^{^{'}} = y^{2}

n = 2 \sum \infty \frac{2}{n ^{3} - n}

What is (\partial)/(\partial θ)(e^rcos(θ)) ?
The answer to (\partial)/(\partial θ)(e^rcos(θ)) is -e^rsin(θ)