What is the derivative of (2pi-xcos(x)/(x-2pi)) ?

The derivative of (2pi-xcos(x)/(x-2pi)) is (x^2sin(x)-2pixsin(x)+2picos(x)-2pi)/((x-2pi)^2)

What is the first derivative of (2pi-xcos(x)/(x-2pi)) ?

The first derivative of (2pi-xcos(x)/(x-2pi)) is (x^2sin(x)-2pixsin(x)+2picos(x)-2pi)/((x-2pi)^2)

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\frac{d}{d x} (\frac{2 π - x cos ( x )}{x - 2 π})

\frac{x ^{2} sin ( x ) - 2 π x sin ( x ) + 2 π cos ( x ) - 2 π}{( x - 2 π ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 π - x cos ( x )}{x - 2 π})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 π - x cos ( x ) ) ( x - 2 π ) - \frac{d}{d x} ( x - 2 π ) ( 2 π - x cos ( x ) )}{( x - 2 π ) ^{2}}

\frac{d}{d x} (2 π - x cos (x)) = x sin (x) - cos (x)

\frac{d}{d x} (x - 2 π) = 1

= \frac{( x sin ( x ) - cos ( x ) ) ( x - 2 π ) - 1 \cdot ( 2 π - x cos ( x ) )}{( x - 2 π ) ^{2}}

Simplify

\frac{( x sin ( x ) - cos ( x ) ) ( x - 2 π ) - 1 \cdot ( 2 π - x cos ( x ) )}{( x - 2 π ) ^{2}} : \frac{x ^{2} sin ( x ) - 2 π x sin ( x ) + 2 π cos ( x ) - 2 π}{( x - 2 π ) ^{2}}

= \frac{x ^{2} sin ( x ) - 2 π x sin ( x ) + 2 π cos ( x ) - 2 π}{( x - 2 π ) ^{2}}

\frac{d}{d x} (7 e^{x^{2} + 1})

\int (5 - x) d x

\frac{1}{s ( s ^{1} + 1 )}

\frac{d}{d x} (2^{3})

\frac{d}{d x} (a^{2} x^{2} + b x + 49)

What is the derivative of (2pi-xcos(x)/(x-2pi)) ?
The derivative of (2pi-xcos(x)/(x-2pi)) is (x^2sin(x)-2pixsin(x)+2picos(x)-2pi)/((x-2pi)^2)
What is the first derivative of (2pi-xcos(x)/(x-2pi)) ?
The first derivative of (2pi-xcos(x)/(x-2pi)) is (x^2sin(x)-2pixsin(x)+2picos(x)-2pi)/((x-2pi)^2)