What is the derivative of a^2x^2+bx+49 ?

The derivative of a^2x^2+bx+49 is 2a^2x+b

What is the first derivative of a^2x^2+bx+49 ?

The first derivative of a^2x^2+bx+49 is 2a^2x+b

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\frac{d}{d x} (a^{2} x^{2} + b x + 49)

2 a^{2} x + b

Solution steps

\frac{d}{d x} (a^{2} x^{2} + b x + 49)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a^{2} x^{2}) + \frac{d}{d x} (b x) + \frac{d}{d x} (49)

\frac{d}{d x} (a^{2} x^{2}) = 2 a^{2} x

\frac{d}{d x} (b x) = b

\frac{d}{d x} (49) = 0

= 2 a^{2} x + b + 0

Simplify

= 2 a^{2} x + b

\int (x^{2} + x + 1) \cdot sin (x) d x

\int \frac{arctan ( 4 x )}{1 + 16 x ^{2}} d x

y = 5 x - 2 x^{2}, (- 3, - 33)

\int 1 + 2 cos (2 θ) + \frac{1}{2} (1 + cos (4 θ)) d θ

(12 x^{2} + y - 1) d x - (10 y - x) d y = 0, y (1) = 0

What is the derivative of a^2x^2+bx+49 ?
The derivative of a^2x^2+bx+49 is 2a^2x+b
What is the first derivative of a^2x^2+bx+49 ?
The first derivative of a^2x^2+bx+49 is 2a^2x+b