What is (\partial)/(\partial x)(x^2y^2) ?

The answer to (\partial)/(\partial x)(x^2y^2) is 2xy^2

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(\partial)/(\partial x)(x^2y^2)

\frac{\partial}{\partial x} (x^{2} y^{2})

2 x y^{2}

Solution steps

\frac{\partial}{\partial x} (x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= y^{2} \cdot 2 x^{2 - 1}

Simplify

= 2 x y^{2}

\frac{\partial}{\partial x} (cos (sin (x^{2})))

\frac{d}{d v} (ln (cosh (2 v)) - \frac{1}{2} tanh^{2} (2 v))

\frac{10}{s ( s + 1 )}

\frac{d}{d x} (\frac{f ( x )}{x ^{2}})

\frac{d}{d x} (3 x^{4} - 1)

What is (\partial)/(\partial x)(x^2y^2) ?
The answer to (\partial)/(\partial x)(x^2y^2) is 2xy^2