What is the solution for (dx)/(dt)-4x=cos(3t) ?

The solution for (dx)/(dt)-4x=cos(3t) is x=(3sin(3t))/(25)-(4cos(3t))/(25)+c_{1}e^{4t}

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(dx)/(dt)-4x=cos(3t)

\frac{d x}{d t} - 4 x = cos (3 t)

x = \frac{3 sin ( 3 t )}{25} - \frac{4 cos ( 3 t )}{25} + c_{1} e^{4 t}

Solution steps

\frac{d x}{d t} - 4 x = cos (3 t)

Solve linear ODE:

x = \frac{3 sin ( 3 t )}{25} - \frac{4 cos ( 3 t )}{25} + c_{1} e^{4 t}

x = \frac{3 sin ( 3 t )}{25} - \frac{4 cos ( 3 t )}{25} + c_{1} e^{4 t}

\int_{0}^{\infty} e^{- 6 x} d x

n = 0 \sum \infty n - 1

\frac{d}{d x} (ln^{2} (\frac{x}{3}))

\int \frac{1}{3 y} d y

\int (\frac{tan ( x )}{cos ^{2} ( x )}) d x

What is the solution for (dx)/(dt)-4x=cos(3t) ?
The solution for (dx)/(dt)-4x=cos(3t) is x=(3sin(3t))/(25)-(4cos(3t))/(25)+c_{1}e^{4t}