What is the derivative of f(x)= 1/(4x^2) ?

The derivative of f(x)= 1/(4x^2) is -1/(2x^3)

What is the first derivative of f(x)= 1/(4x^2) ?

The first derivative of f(x)= 1/(4x^2) is -1/(2x^3)

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derivative of

f (x) = \frac{1}{4 x ^{2}}

- \frac{1}{2 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{4 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{4} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} (- 2 x^{- 2 - 1})

Simplify

\frac{1}{4} (- 2 x^{- 2 - 1}) : - \frac{1}{2 x ^{3}}

= - \frac{1}{2 x ^{3}}

\int x^{3} y^{2} d y

\int \frac{1}{x 4 + x ^{2}} d x

y^{^{'}} = k y

y^{^{''}} - y^{^{'}} - 2 y = 4 x^{2}, y (0) = - 1, y^{^{'}} (0) = 1

x \to 16 lim (4 x)

What is the derivative of f(x)= 1/(4x^2) ?
The derivative of f(x)= 1/(4x^2) is -1/(2x^3)
What is the first derivative of f(x)= 1/(4x^2) ?
The first derivative of f(x)= 1/(4x^2) is -1/(2x^3)