What is the limit as x approaches 16 of sqrt(4x) ?

The limit as x approaches 16 of sqrt(4x) is 8

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limit as x approaches 16 of sqrt(4x)

x \to 16 lim (4 x)

8

Solution steps

x \to 16 lim (4 x)

Plug in the value

x = 16

= 4 \cdot 16

Simplify

4 \cdot 16 : 8

= 8

\int_{0}^{5} π (\frac{20 - 4 x}{5})^{2} d x

\int 3 u d u

(8.1) (24.9)

x^{2} y^{^{'}} = y^{2} + x y

(3, 3), (- 3, - 1)

What is the limit as x approaches 16 of sqrt(4x) ?
The limit as x approaches 16 of sqrt(4x) is 8