What is the derivative of 1-4/(x+3) ?

The derivative of 1-4/(x+3) is 4/((x+3)^2)

What is the first derivative of 1-4/(x+3) ?

The first derivative of 1-4/(x+3) is 4/((x+3)^2)

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\frac{d}{d x} (1 - \frac{4}{x + 3})

\frac{4}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (1 - \frac{4}{x + 3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{4}{x + 3})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{4}{x + 3}) = - \frac{4}{( x + 3 ) ^{2}}

= 0 - (- \frac{4}{( x + 3 ) ^{2}})

Simplify

= \frac{4}{( x + 3 ) ^{2}}

n = 0 \sum \infty (\frac{e}{π})^{n}

\int cot (3 x) csc^{4} (3 x) d x

\int 45

f (x) = 3 x^{4}, at x = - 2, 48

(e^{- 2 t} - 1)^{2}

What is the derivative of 1-4/(x+3) ?
The derivative of 1-4/(x+3) is 4/((x+3)^2)
What is the first derivative of 1-4/(x+3) ?
The first derivative of 1-4/(x+3) is 4/((x+3)^2)