What is the derivative of ln((x+1^2)) ?

The derivative of ln((x+1^2)) is 2/(x+1)

What is the first derivative of ln((x+1^2)) ?

The first derivative of ln((x+1^2)) is 2/(x+1)

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\frac{d}{d x} (ln ((x + 1)^{2}))

\frac{2}{x + 1}

Solution steps

\frac{d}{d x} (ln ((x + 1)^{2}))

Apply the chain rule:

\frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} ((x + 1)^{2})

= \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} ((x + 1)^{2})

\frac{d}{d x} ((x + 1)^{2}) = 2 (x + 1)

= \frac{1}{( x + 1 ) ^{2}} \cdot 2 (x + 1)

Simplify

\frac{1}{( x + 1 ) ^{2}} \cdot 2 (x + 1) : \frac{2}{x + 1}

= \frac{2}{x + 1}

\frac{\partial}{\partial x} (\frac{1}{x - a})

\int sin (x) sec^{2} (x) d x

\frac{\partial}{\partial x} (4 x^{3} + 4 x y^{2})

e^{- 3 t}

(t^{2} + 16) (\frac{d x}{d t}) = (x^{2} + 25), x (0) = 5

What is the derivative of ln((x+1^2)) ?
The derivative of ln((x+1^2)) is 2/(x+1)
What is the first derivative of ln((x+1^2)) ?
The first derivative of ln((x+1^2)) is 2/(x+1)