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Popular >

xy^'+y=y^2,y(1)=-7

Solution

x y^{^{'}} + y = y^{2}, y (1) = - 7

Solution

y = \frac{7}{- 8 x + 7}

Solution steps

x y^{'} (x) + y = y^{2}

Solve Bernoulli ODE:

y = \frac{7}{- 8 x + 7}

y = \frac{7}{- 8 x + 7}

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Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=y^2,y(1)=-7 ?
The solution for xy^'+y=y^2,y(1)=-7 is y= 7/(-8x+7)