What is the derivative of \sqrt[9]{x}-9e^x ?

The derivative of \sqrt[9]{x}-9e^x is 1/(9x^{8/9)}-9e^x

What is the first derivative of \sqrt[9]{x}-9e^x ?

The first derivative of \sqrt[9]{x}-9e^x is 1/(9x^{8/9)}-9e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{9 x ^{\frac{8}{9}}} - 9 e^{x}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

= \frac{1}{9 x ^{\frac{8}{9}}} - 9 e^{x}

x \to 2 lim (\frac{1}{x - 1})

\frac{d}{d x} ((x^{3} + 4 x)^{(x^{5} + 3 x^{2})})

\int 1 - 2 x + x^{2} d x

x \to 0 lim (\frac{ln ( 1 + x )}{x})

f (x) = x^{2} + 9, (5, 34)

What is the derivative of \sqrt[9]{x}-9e^x ?
The derivative of \sqrt[9]{x}-9e^x is 1/(9x^{8/9)}-9e^x
What is the first derivative of \sqrt[9]{x}-9e^x ?
The first derivative of \sqrt[9]{x}-9e^x is 1/(9x^{8/9)}-9e^x