What is the tangent of f(x)=x^2+9,(5,34) ?

The tangent of f(x)=x^2+9,(5,34) is y=10x-16

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tangent of f(x)=x^2+9,(5,34)

tangent of

f (x) = x^{2} + 9, (5, 34)

y = 10 x - 16

Solution steps

Find the slope of

f (x) = x^{2} + 9 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} + 9

(5, 34) : m = 10

Find the line with slope m=

10

and passing through

(5, 34) : y = 10 x - 16

y = 10 x - 16

\int \frac{( 9 x ^{2} + 5 x + 9 )}{( x ^{2} + 1 ) ^{2}} d x

(x^{6} + y^{6}) d x + 6 x y^{5} d y = 0

f (t) = cos^{2} (t)

\frac{d}{d x} (ln (1 - 4 x))

x + 10

What is the tangent of f(x)=x^2+9,(5,34) ?
The tangent of f(x)=x^2+9,(5,34) is y=10x-16