What is the tangent of f(x)= 1/(x-1),(-7,-1/8) ?

The tangent of f(x)= 1/(x-1),(-7,-1/8) is y=-1/64 x-15/64

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tangent of f(x)= 1/(x-1),(-7,-1/8)

tangent of

f (x) = \frac{1}{x - 1}, (- 7, - \frac{1}{8})

y = - \frac{1}{64} x - \frac{15}{64}

Solution steps

Find the slope of

f (x) = \frac{1}{x - 1} : \frac{df ( x )}{d x} = - \frac{1}{( x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{1}{x - 1}

(- 7, - \frac{1}{8}) : m = - \frac{1}{64}

Find the line with slope m=

- \frac{1}{64}

and passing through

(- 7, - \frac{1}{8}) : y = - \frac{1}{64} x - \frac{15}{64}

y = - \frac{1}{64} x - \frac{15}{64}

\frac{d}{d x} (3 x^{5} (7 - 2 x)^{7})

(x^{2} - 4), y = 0, x = - 4, x = 3

\int \frac{e ^{5 s i n (x)}}{sec ( x )} d x

\frac{d}{d x} (\frac{( 3 x - 5 ) ^{3}}{( 2 x ^{2} + 1 ) ^{4}})

\frac{\partial}{\partial y} (y)

What is the tangent of f(x)= 1/(x-1),(-7,-1/8) ?
The tangent of f(x)= 1/(x-1),(-7,-1/8) is y=-1/64 x-15/64