What is derivative of f(x)=((3x^2)/(2x+4))^3,x=2 ?

The answer to derivative of f(x)=((3x^2)/(2x+4))^3,x=2 is 243/32

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derivative of f(x)=((3x^2)/(2x+4))^3,x=2

derivative of

f (x) = (\frac{3 x ^{2}}{2 x + 4})^{3}, x = 2

\frac{243}{32}

Solution steps

\frac{d}{d x} ((\frac{3 x ^{2}}{2 x + 4})^{3}) = \frac{81 x ^{5} ( x + 4 )}{2 ( 2 x + 4 ) ^{2} ( x + 2 ) ^{2}}

Find the value of

\frac{81 x ^{5} ( x + 4 )}{2 ( 2 x + 4 ) ^{2} ( x + 2 ) ^{2}}

for

x = 2 : \frac{243}{32}

\frac{243}{32}

100 x + 0.01 x^{2}

\frac{d}{d x} (4 (2 - x^{2})^{2})

\int_{0}^{l n (2)} 4 (2 - x e^{x}) d x

x^{2} \frac{d ^{2} y}{d x ^{2}} + x \frac{d y}{d x} + y = 0

f (x) = e^{t a n (x)}

What is derivative of f(x)=((3x^2)/(2x+4))^3,x=2 ?
The answer to derivative of f(x)=((3x^2)/(2x+4))^3,x=2 is 243/32