What is the derivative of 4(2-x^2^2) ?

The derivative of 4(2-x^2^2) is -16x(2-x^2)

What is the first derivative of 4(2-x^2^2) ?

The first derivative of 4(2-x^2^2) is -16x(2-x^2)

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\frac{d}{d x} (4 (2 - x^{2})^{2})

- 16 x (2 - x^{2})

Solution steps

\frac{d}{d x} (4 (2 - x^{2})^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} ((2 - x^{2})^{2})

Apply the chain rule:

2 (2 - x^{2}) \frac{d}{d x} (2 - x^{2})

= 2 (2 - x^{2}) \frac{d}{d x} (2 - x^{2})

\frac{d}{d x} (2 - x^{2}) = - 2 x

= 4 \cdot 2 (2 - x^{2}) (- 2 x)

Simplify

= - 16 x (2 - x^{2})

\int_{0}^{l n (2)} 4 (2 - x e^{x}) d x

x^{2} \frac{d ^{2} y}{d x ^{2}} + x \frac{d y}{d x} + y = 0

f (x) = e^{t a n (x)}

\frac{d}{d x} (1 - (x^{2} + y^{2})^{\frac{1}{3}})

\int 4 x - 3 - x^{2} d x

What is the derivative of 4(2-x^2^2) ?
The derivative of 4(2-x^2^2) is -16x(2-x^2)
What is the first derivative of 4(2-x^2^2) ?
The first derivative of 4(2-x^2^2) is -16x(2-x^2)