What is the derivative of-15x^4+270x^2 ?

The derivative of-15x^4+270x^2 is -60x^3+540x

What is the first derivative of-15x^4+270x^2 ?

The first derivative of-15x^4+270x^2 is -60x^3+540x

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derivative of

- 15 x^{4} + 270 x^{2}

- 60 x^{3} + 540 x

Solution steps

\frac{d}{d x} (- 15 x^{4} + 270 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (15 x^{4}) + \frac{d}{d x} (270 x^{2})

\frac{d}{d x} (15 x^{4}) = 60 x^{3}

\frac{d}{d x} (270 x^{2}) = 540 x

= - 60 x^{3} + 540 x

\frac{d}{d x} (5 e^{6 x})

\int 8 x^{3} e^{- x^{2}} d x

y^{^{'}} = y (x y^{4} + 2)

x \to 9 lim ((x - 9)^{4})

\frac{d}{d x} (sin (x) - x)

What is the derivative of-15x^4+270x^2 ?
The derivative of-15x^4+270x^2 is -60x^3+540x
What is the first derivative of-15x^4+270x^2 ?
The first derivative of-15x^4+270x^2 is -60x^3+540x