What is the solution for x(dy)/(dx)+1y=6y^2,y(1)=-1 ?

The solution for x(dy)/(dx)+1y=6y^2,y(1)=-1 is y= 1/(-7x+6)

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x(dy)/(dx)+1y=6y^2,y(1)=-1

x \frac{d y}{d x} + 1 y = 6 y^{2}, y (1) = - 1

y = \frac{1}{- 7 x + 6}

Solution steps

x \frac{d y}{d x} + 1 y = 6 y^{2}

Solve Bernoulli ODE:

y = \frac{1}{- 7 x + 6}

y = \frac{1}{- 7 x + 6}

n = 1 \sum \infty \frac{1}{2 n + 3}

x^{2} + 6

\frac{d}{d x} (- 49 sin (7 x))

\int 4 sin (5 x) + 5 sin (4 x) d x

2^{x} \cdot ln (2)

What is the solution for x(dy)/(dx)+1y=6y^2,y(1)=-1 ?
The solution for x(dy)/(dx)+1y=6y^2,y(1)=-1 is y= 1/(-7x+6)