What is area x^3-6x^2+8x,x^2-4x ?

The answer to area x^3-6x^2+8x,x^2-4x is 71/6

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area x^3-6x^2+8x,x^2-4x

area

x^{3} - 6 x^{2} + 8 x, x^{2} - 4 x

\frac{71}{6}

Decimal Notation

11.83333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} x^{3} - 6 x^{2} + 8 x - (x^{2} - 4 x) d x

Solve

\int_{0}^{4} x^{3} - 6 x^{2} + 8 x - (x^{2} - 4 x) d x : \frac{71}{6}

The area is:

= \frac{71}{6}

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