What is the solution for y^{''}-6y^'+9y=t^{-4}e^{3t} ?

The solution for y^{''}-6y^'+9y=t^{-4}e^{3t} is y=c_{1}e^{3t}+c_{2}te^{3t}+(e^{3t})/(6t^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-6y^'+9y=t^{-4}e^{3t}

y^{^{''}} - 6 y^{^{'}} + 9 y = t^{- 4} e^{3 t}

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{e ^{3 t}}{6 t ^{2}}

Solution steps

y^{''} (t) - 6 y^{'} (t) + 9 y = t^{- 4} e^{3 t}

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{e ^{3 t}}{6 t ^{2}}

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{e ^{3 t}}{6 t ^{2}}

f (x) = (2 x - 8)^{5}

2 x^{3} + 4 x^{2} - 5 x - 3

\frac{d}{d x} (2 sin (5 x))

x \to 0 + lim (8 x ln (x))

F (t) = (3 t - 1)^{4} (2 t + 1)^{- 3}

What is the solution for y^{''}-6y^'+9y=t^{-4}e^{3t} ?
The solution for y^{''}-6y^'+9y=t^{-4}e^{3t} is y=c_{1}e^{3t}+c_{2}te^{3t}+(e^{3t})/(6t^2)