What is the derivative of x^2(ln(x)) ?

The derivative of x^2(ln(x)) is 2xln(x)+x

What is the first derivative of x^2(ln(x)) ?

The first derivative of x^2(ln(x)) is 2xln(x)+x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} (ln (x)))

2 x ln (x) + x

Solution steps

\frac{d}{d x} (x^{2} (ln (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = ln (x)

= \frac{d}{d x} (x^{2}) ln (x) + \frac{d}{d x} (ln (x)) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 x ln (x) + \frac{1}{x} x^{2}

\frac{1}{x} x^{2} = x

= 2 x ln (x) + x

\frac{d}{d x} (ln (6 sec (x)))

f (x) = 2 x^{2} - 3 x + 1, 1, 2

y = 9 x, y = x^{2}

\int \frac{25 x ^{2} - 9}{x ^{3}} d x

z \to 0 lim (\frac{z ^{2}}{z})

What is the derivative of x^2(ln(x)) ?
The derivative of x^2(ln(x)) is 2xln(x)+x
What is the first derivative of x^2(ln(x)) ?
The first derivative of x^2(ln(x)) is 2xln(x)+x