What is area f(x)=2x^2-3x+1,1,2 ?

The answer to area f(x)=2x^2-3x+1,1,2 is 7/6

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area f(x)=2x^2-3x+1,1,2

area

f (x) = 2 x^{2} - 3 x + 1, 1, 2

\frac{7}{6}

Decimal Notation

1.16666 \dots

Solution steps

Apply the area formula:

\int_{1}^{2} 2 x^{2} - 3 x + 1 d x

Solve

\int_{1}^{2} 2 x^{2} - 3 x + 1 d x : \frac{7}{6}

The area is:

= \frac{7}{6}

y = 9 x, y = x^{2}

\int \frac{25 x ^{2} - 9}{x ^{3}} d x

z \to 0 lim (\frac{z ^{2}}{z})

\int e^{7 x} cos (6 x) d x

n \to \infty lim (0. 6^{n})