What is the limit as n approaches infinity of 0.6^n ?

The limit as n approaches infinity of 0.6^n is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as n approaches infinity of 0.6^n

n \to \infty lim (0. 6^{n})

0

Solution steps

n \to \infty lim (0. 6^{n})

Apply the common limit:

x \to \infty lim (a^{x}) = 0, 0 < a < 1

= 0

x \to 0 + lim (2 + 3 e^{- \frac{3}{x}})

\frac{1}{x - 1}

\frac{d}{d x} (x^{π^{2}} + (π^{2})^{x})

\frac{d}{d x} (\frac{sin ( 2 x )}{cos ( 2 x )})

\frac{d}{d x} (e^{x - 1} - x + 1)

What is the limit as n approaches infinity of 0.6^n ?
The limit as n approaches infinity of 0.6^n is 0