What is the derivative of x^{pi^2}+(pi^2^x) ?

The derivative of x^{pi^2}+(pi^2^x) is pi^2x^{pi^2-1}+2ln(pi)pi^{2x}

What is the first derivative of x^{pi^2}+(pi^2^x) ?

The first derivative of x^{pi^2}+(pi^2^x) is pi^2x^{pi^2-1}+2ln(pi)pi^{2x}

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\frac{d}{d x} (x^{π^{2}} + (π^{2})^{x})

π^{2} x^{π^{2} - 1} + 2 ln (π) π^{2 x}

Solution steps

\frac{d}{d x} (x^{π^{2}} + (π^{2})^{x})

Simplify

x^{π^{2}} + (π^{2})^{x} : x^{π^{2}} + π^{2 x}

= \frac{d}{d x} (x^{π^{2}} + π^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{π^{2}}) + \frac{d}{d x} (π^{2 x})

\frac{d}{d x} (x^{π^{2}}) = π^{2} x^{π^{2} - 1}

\frac{d}{d x} (π^{2 x}) = 2 ln (π) π^{2 x}

= π^{2} x^{π^{2} - 1} + 2 ln (π) π^{2 x}

\frac{d}{d x} (\frac{sin ( 2 x )}{cos ( 2 x )})

\frac{d}{d x} (e^{x - 1} - x + 1)

f (x) = x^{8} e^{x}

x y^{^{'}} + y = e^{x}, y (1) = 5

\int_{1}^{5} 26 d x

What is the derivative of x^{pi^2}+(pi^2^x) ?
The derivative of x^{pi^2}+(pi^2^x) is pi^2x^{pi^2-1}+2ln(pi)pi^{2x}
What is the first derivative of x^{pi^2}+(pi^2^x) ?
The first derivative of x^{pi^2}+(pi^2^x) is pi^2x^{pi^2-1}+2ln(pi)pi^{2x}