What is (\partial)/(\partial y)(-y/x) ?

The answer to (\partial)/(\partial y)(-y/x) is -1/x

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(\partial)/(\partial y)(-y/x)

\frac{\partial}{\partial y} (- \frac{y}{x})

- \frac{1}{x}

Solution steps

\frac{\partial}{\partial y} (- \frac{y}{x})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{x} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= - \frac{1}{x} \cdot 1

Simplify

= - \frac{1}{x}

\int_{0}^{\frac{π}{3}} cos (\frac{2 x}{3}) d x

x^{2} + 5 x + 1, x^{3} + x^{2} + x + 1

\int \frac{1}{( x - 2 ) ^{3}} d x

\int x^{3} (x^{4} + 16)^{4} d x

\frac{d}{d x} (- cot (x) csc (x))

What is (\partial)/(\partial y)(-y/x) ?
The answer to (\partial)/(\partial y)(-y/x) is -1/x