What is the sum from n=0 to infinity of 2/(1.15^n) ?

The sum from n=0 to infinity of 2/(1.15^n) is 15.33333…

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sum from n=0 to infinity of 2/(1.15^n)

n = 0 \sum \infty \frac{2}{1.1 5 ^{n}}

15.33333 \dots

Solution steps

n = 0 \sum \infty \frac{2}{1.1 5 ^{n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 0 \sum \infty \frac{1}{1.1 5 ^{n}}

Apply Series Geometric Test:

7.66666 \dots

= 2 \cdot 7.66666 \dots

Simplify

= 15.33333 \dots

y^{^{''}} + 25 y = - 30 sec (5 t)

\frac{d}{d x} (\frac{3 x ^{2} - 6}{2 x + 3})

\frac{d}{d x} (e^{x} \cdot cos (2 x))

\frac{d}{d x} (tan (x) sin (x))

4 x e^{x}

What is the sum from n=0 to infinity of 2/(1.15^n) ?
The sum from n=0 to infinity of 2/(1.15^n) is 15.33333…