What is the integral of e^{-cos(x)}sin(x) ?

The integral of e^{-cos(x)}sin(x) is e^{-cos(x)}+C

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integral of e^{-cos(x)}sin(x)

\int e^{- c o s (x)} sin (x) d x

e^{- c o s (x)} + C

Solution steps

\int e^{- c o s (x)} sin (x) d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = - cos (x)

= e^{- c o s (x)}

Add a constant to the solution

= e^{- c o s (x)} + C

\frac{\partial}{\partial x} (\frac{1}{4 x})

\frac{\partial}{\partial x} (3 x e^{7 x y})

\int_{0}^{7} \frac{4 t}{( t - 8 ) ^{2}} d t

n = 0 \sum \infty \frac{1}{n ^{3}}

\frac{d}{d x} (\frac{4}{x - 1})

What is the integral of e^{-cos(x)}sin(x) ?
The integral of e^{-cos(x)}sin(x) is e^{-cos(x)}+C