What is the solution for 100y^{''}+60y^'-27y=0 ?

The solution for 100y^{''}+60y^'-27y=0 is y=c_{1}e^{(3t)/(10)}+c_{2}e^{-(9t)/(10)}

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100y^{''}+60y^'-27y=0

100 y^{^{''}} + 60 y^{^{'}} - 27 y = 0

y = c_{1} e^{\frac{3 t}{10}} + c_{2} e^{- \frac{9 t}{10}}

Solution steps

100 y^{''} (t) + 60 y^{'} (t) - 27 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{3 t}{10}} + c_{2} e^{- \frac{9 t}{10}}

y = c_{1} e^{\frac{3 t}{10}} + c_{2} e^{- \frac{9 t}{10}}

7 x, \frac{7}{4} x, 78 - x^{2}, y = 0

y^{^{''}} + 2 \cdot y^{^{'}} + 26 \cdot y = e^{- x} cos (5 \cdot x)

\int \frac{8000 - 2000 x}{( x ^{2} - 8 x + 17 ) ^{2}} d x

\frac{d}{d x} (x^{5} \cdot tan (x))

What is the solution for 100y^{''}+60y^'-27y=0 ?
The solution for 100y^{''}+60y^'-27y=0 is y=c_{1}e^{(3t)/(10)}+c_{2}e^{-(9t)/(10)}