What is the limit as x approaches 0 of x/(x^2-4x) ?

The limit as x approaches 0 of x/(x^2-4x) is -1/4

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limit as x approaches 0 of x/(x^2-4x)

x \to 0 lim (\frac{x}{x ^{2} - 4 x})

- \frac{1}{4}

Decimal Notation

- 0.25

Solution steps

x \to 0 lim (\frac{x}{x ^{2} - 4 x})

Simplify

\frac{x}{x ^{2} - 4 x} : \frac{1}{x - 4}

= x \to 0 lim (\frac{1}{x - 4})

Plug in the value

x = 0

= \frac{1}{0 - 4}

Simplify

= - \frac{1}{4}

\int \frac{1}{( a x + b ) ^{2}} d x

x \to 3 lim (\frac{1}{∣ x - 3 ∣})

\frac{d}{d x} (x^{2} \cdot 2 x)

\frac{d}{d x} (x^{2} ln (\frac{x}{2}))

x \to \frac{2}{3} lim (\frac{3 x - 2}{3 x ^{2} - 11 x + 6})

What is the limit as x approaches 0 of x/(x^2-4x) ?
The limit as x approaches 0 of x/(x^2-4x) is -1/4