What is the solution for (dy)/(dx)+3xy^2=0,y(0)=1 ?

The solution for (dy)/(dx)+3xy^2=0,y(0)=1 is y= 2/(3x^2+2)

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(dy)/(dx)+3xy^2=0,y(0)=1

\frac{d y}{d x} + 3 x y^{2} = 0, y (0) = 1

y = \frac{2}{3 x ^{2} + 2}

Solution steps

\frac{d y}{d x} + 3 x y^{2} = 0

Solve separable ODE:

y = \frac{2}{3 x ^{2} + 2}

y = \frac{2}{3 x ^{2} + 2}

\frac{d}{d x} ((\frac{6 x ^{2}}{4 - x})^{3})

n = 0 \sum \infty \frac{n}{n ^{4} + 1}

\frac{d}{d x} (\frac{x + 9}{x ^{3} + x - 8})

\int_{- 1}^{3} \frac{x}{x ^{2} + 1} d x

- 6 cos (t)

What is the solution for (dy)/(dx)+3xy^2=0,y(0)=1 ?
The solution for (dy)/(dx)+3xy^2=0,y(0)=1 is y= 2/(3x^2+2)