What is the slope ofintercept (-5,-2),(5,12) ?

The slope ofintercept (-5,-2),(5,12) is y= 7/5 x+5

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slope ofintercept (-5,-2),(5,12)

slope intercept

(- 5, - 2), (5, 12)

y = \frac{7}{5} x + 5

Solution steps

Compute the slope

(- 5, - 2), (5, 12) : m = \frac{7}{5}

Compute the

y

intercept:

b = 5

Construct the line equation

y = mx + b

where

m = \frac{7}{5}

and

b = 5

y = \frac{7}{5} x + 5

y^{^{''}} + \frac{1}{2} y^{^{'}} + \frac{1}{16} y = 0, y (0) = 0, y^{^{'}} (0) = 5

\frac{\partial}{\partial y} (e^{x y} - z)

y^{^{''}} + 12 y^{^{'}} + 37 y = 0

x \to - 5 - lim (\frac{- 2}{x ^{2} - 25})

\int \frac{8}{64 - x ^{2}} d x

What is the slope ofintercept (-5,-2),(5,12) ?
The slope ofintercept (-5,-2),(5,12) is y= 7/5 x+5