What is the solution for xy^'+2yln(x)=3 ?

The solution for xy^'+2yln(x)=3 is y=(3sqrt(pi)\erfi(ln(x)))/(2e^{ln^2(x))}+(c_{1})/(e^{ln^2(x))}

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xy^'+2yln(x)=3

x y^{^{'}} + 2 y ln (x) = 3

y = \frac{3 π erfi ( ln ( x ) )}{2 e ^{l n^{2} (x)}} + \frac{c _{1}}{e ^{l n^{2} (x)}}

Solution steps

x y^{'} (x) + 2 y ln (x) = 3

Solve linear ODE:

y = \frac{3 π erfi ( ln ( x ) )}{2 e ^{l n^{2} (x)}} + \frac{c _{1}}{e ^{l n^{2} (x)}}

y = \frac{3 π erfi ( ln ( x ) )}{2 e ^{l n^{2} (x)}} + \frac{c _{1}}{e ^{l n^{2} (x)}}

\int_{1}^{3} \frac{x ^{2} + 8}{4 x - x ^{2}} d x

y^{^{'}} = x y

y = ln (x + x^{2} - 1)

x \to 0 + lim (ln (\frac{1}{x}))

x \to 1 lim (7 ∣ x + 1 ∣ - 4)

What is the solution for xy^'+2yln(x)=3 ?
The solution for xy^'+2yln(x)=3 is y=(3sqrt(pi)\erfi(ln(x)))/(2e^{ln^2(x))}+(c_{1})/(e^{ln^2(x))}