What is the limit as x approaches 0+of ln(1/x) ?

The limit as x approaches 0+of ln(1/x) is infinity

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limit as x approaches 0+of ln(1/x)

x \to 0 + lim (ln (\frac{1}{x}))

\infty

Solution steps

x \to 0 + lim (ln (\frac{1}{x}))

Apply log rule:

lo g_{a} (\frac{1}{x}) = - lo g_{a} (x)

= x \to 0 + lim (- ln (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to 0 + lim (ln (x))

Apply the common limit:

x \to 0 + lim (ln (x)) = - \infty

= - (- \infty)

Simplify

= \infty

x \to 1 lim (7 ∣ x + 1 ∣ - 4)

y = (x - 1) (x^{2} + x + 1)

\frac{d y}{d x} = \frac{2 x}{y + 1}

\int_{1}^{1000} \frac{25}{x ^{3}} d x

x^{2} y^{^{'}} + 2 x y = ln (x), y (1) = 2

What is the limit as x approaches 0+of ln(1/x) ?
The limit as x approaches 0+of ln(1/x) is infinity