What is the solution for (dy)/(dx)=(2x)/(y+1) ?

The solution for (dy)/(dx)=(2x)/(y+1) is y=-1+sqrt(2(x^2+c_{1))+1},y=-sqrt(2(x^2+c_{1))+1}-1

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(dy)/(dx)=(2x)/(y+1)

\frac{d y}{d x} = \frac{2 x}{y + 1}

y = - 1 + 2 (x^{2} + c_{1}) + 1, y = - 2 (x^{2} + c_{1}) + 1 - 1

Solution steps

\frac{d y}{d x} = \frac{2 x}{y + 1}

Solve separable ODE:

y = - 1 + 2 (x^{2} + c_{1}) + 1, y = - 2 (x^{2} + c_{1}) + 1 - 1

y = - 1 + 2 (x^{2} + c_{1}) + 1, y = - 2 (x^{2} + c_{1}) + 1 - 1

\int_{1}^{1000} \frac{25}{x ^{3}} d x

x^{2} y^{^{'}} + 2 x y = ln (x), y (1) = 2

\frac{( x ^{2} )}{x + 2}

x \to 0 lim (\frac{cos ( \frac{π}{2} - x )}{x})

n = 2 \sum \infty 5 \cdot (- \frac{3}{4})^{n}

What is the solution for (dy)/(dx)=(2x)/(y+1) ?
The solution for (dy)/(dx)=(2x)/(y+1) is y=-1+sqrt(2(x^2+c_{1))+1},y=-sqrt(2(x^2+c_{1))+1}-1