What is the limit as x approaches 0 of (cos(pi/2-x))/x ?

The limit as x approaches 0 of (cos(pi/2-x))/x is 1

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limit as x approaches 0 of (cos(pi/2-x))/x

x \to 0 lim (\frac{cos ( \frac{π}{2} - x )}{x})

1

Solution steps

x \to 0 lim (\frac{cos ( \frac{π}{2} - x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{cos ( x )}{1})

= x \to 0 lim (\frac{cos ( x )}{1})

Plug in the value

x = 0

= \frac{cos ( 0 )}{1}

Simplify

\frac{cos ( 0 )}{1} : 1

= 1

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y^{^{''}} + 5 y^{^{'}} + 4 y = t^{2} e^{7 t}

\int_{0}^{l n (5)} e^{x} - e^{- 2 x} d x

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What is the limit as x approaches 0 of (cos(pi/2-x))/x ?
The limit as x approaches 0 of (cos(pi/2-x))/x is 1