What is the integral from 0 to ln(5) of e^x-e^{-2x} ?

The integral from 0 to ln(5) of e^x-e^{-2x} is 88/25

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integral from 0 to ln(5) of e^x-e^{-2x}

\int_{0}^{l n (5)} e^{x} - e^{- 2 x} d x

\frac{88}{25}

Decimal Notation

3.52

Solution steps

\int_{0}^{l n (5)} e^{x} - e^{- 2 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{l n (5)} e^{x} d x - \int_{0}^{l n (5)} e^{- 2 x} d x

\int_{0}^{l n (5)} e^{x} d x = 4

\int_{0}^{l n (5)} e^{- 2 x} d x = \frac{12}{25}

= 4 - \frac{12}{25}

Simplify

4 - \frac{12}{25} : \frac{88}{25}

= \frac{88}{25}

\int_{0}^{6} \frac{6 t}{( t - 7 ) ^{2}} d t

\frac{d}{d x} (\frac{x ^{2}}{1 - y ^{2}})

(x + 3) (x - 5)^{7}

x \to + 0 lim (\frac{x ^{2} - 5}{x - 2})

\frac{d y}{1 - y ^{2}} = d x

What is the integral from 0 to ln(5) of e^x-e^{-2x} ?
The integral from 0 to ln(5) of e^x-e^{-2x} is 88/25