What is the tangent of 2x(x+1)^3(x^2+2x+1)^2 ?

The tangent of 2x(x+1)^3(x^2+2x+1)^2 is

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tangent of 2x(x+1)^3(x^2+2x+1)^2

tangent of

2 x (x + 1)^{3} (x^{2} + 2 x + 1)^{2}

y = 2 (8 a_{0}^{7} + 49 a_{0}^{6} + 126 a_{0}^{5} + 175 a_{0}^{4} + 140 a_{0}^{3} + 63 a_{0}^{2} + 14 a_{0} + 1) x - 14 a_{0}^{8} - 84 a_{0}^{7} - 210 a_{0}^{6} - 280 a_{0}^{5} - 210 a_{0}^{4} - 84 a_{0}^{3} - 14 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0} (a_{0} + 1)^{3} (a_{0}^{2} + 2 a_{0} + 1)^{2})

Find the slope of

y = 2 x (x + 1)^{3} (x^{2} + 2 x + 1)^{2} : \frac{d y}{d x} = 2 ((x + 1)^{3} (x^{2} + 2 x + 1)^{2} + x (3 (x + 1)^{2} (x^{2} + 2 x + 1)^{2} + 2 (x^{2} + 2 x + 1) (2 x + 2) (x + 1)^{3}))

Compute the slope of

y = 2 x (x + 1)^{3} (x^{2} + 2 x + 1)^{2}

x = a_{0} : m = 2 (8 a_{0}^{7} + 49 a_{0}^{6} + 126 a_{0}^{5} + 175 a_{0}^{4} + 140 a_{0}^{3} + 63 a_{0}^{2} + 14 a_{0} + 1)

Find the line with slope m=

2 (8 a_{0}^{7} + 49 a_{0}^{6} + 126 a_{0}^{5} + 175 a_{0}^{4} + 140 a_{0}^{3} + 63 a_{0}^{2} + 14 a_{0} + 1)

and passing through

(a_{0}, 2 a_{0} (a_{0} + 1)^{3} (a_{0}^{2} + 2 a_{0} + 1)^{2}) : y = 2 (8 a_{0}^{7} + 49 a_{0}^{6} + 126 a_{0}^{5} + 175 a_{0}^{4} + 140 a_{0}^{3} + 63 a_{0}^{2} + 14 a_{0} + 1) x - 14 a_{0}^{8} - 84 a_{0}^{7} - 210 a_{0}^{6} - 280 a_{0}^{5} - 210 a_{0}^{4} - 84 a_{0}^{3} - 14 a_{0}^{2}

y = 2 (8 a_{0}^{7} + 49 a_{0}^{6} + 126 a_{0}^{5} + 175 a_{0}^{4} + 140 a_{0}^{3} + 63 a_{0}^{2} + 14 a_{0} + 1) x - 14 a_{0}^{8} - 84 a_{0}^{7} - 210 a_{0}^{6} - 280 a_{0}^{5} - 210 a_{0}^{4} - 84 a_{0}^{3} - 14 a_{0}^{2}

(1 + x^{2})^{\frac{3}{2}} x

\int \frac{3}{5 - 2 x} d x

f (x) = 3 sec (8 x)

\int cos^{6} (\frac{x}{2}) d x

What is the tangent of 2x(x+1)^3(x^2+2x+1)^2 ?
The tangent of 2x(x+1)^3(x^2+2x+1)^2 is