What is the derivative of f(x)=3e^x+4/(\sqrt[3]{x)} ?

The derivative of f(x)=3e^x+4/(\sqrt[3]{x)} is 3e^x-4/(3x^{4/3)}

What is the first derivative of f(x)=3e^x+4/(\sqrt[3]{x)} ?

The first derivative of f(x)=3e^x+4/(\sqrt[3]{x)} is 3e^x-4/(3x^{4/3)}

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derivative of

3 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (3 e^{x}) = 3 e^{x}

= 3 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\int 9 e^{- t} d t

x \to \infty lim (- 1 \cdot x)

f (x) = sec^{2} (x) - tan^{2} (x)

\int e^{2 x} \cdot x d x

y^{^{'}} = 0.05 ln (\frac{4000}{y}) y

What is the derivative of f(x)=3e^x+4/(\sqrt[3]{x)} ?
The derivative of f(x)=3e^x+4/(\sqrt[3]{x)} is 3e^x-4/(3x^{4/3)}
What is the first derivative of f(x)=3e^x+4/(\sqrt[3]{x)} ?
The first derivative of f(x)=3e^x+4/(\sqrt[3]{x)} is 3e^x-4/(3x^{4/3)}