What is the derivative of-2x^2+3x-6 ?

The derivative of-2x^2+3x-6 is -4x+3

What is the first derivative of-2x^2+3x-6 ?

The first derivative of-2x^2+3x-6 is -4x+3

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\frac{d}{d x} (- 2 x^{2} + 3 x - 6)

- 4 x + 3

Solution steps

\frac{d}{d x} (- 2 x^{2} + 3 x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (6)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (6) = 0

= - 4 x + 3 - 0

Simplify

= - 4 x + 3

f (x) = 7 e^{x} cos (x)

\frac{d}{d x} (2 x e^{- x} - x^{2} e^{- x})

\frac{d y}{d x} = (\frac{4 x}{( 1 + x ^{2} ) ^{\frac{1}{3}}})

\frac{d}{d x} (3 x^{2} sin (x) tan (x))

ln (x^{2} + 6)

What is the derivative of-2x^2+3x-6 ?
The derivative of-2x^2+3x-6 is -4x+3
What is the first derivative of-2x^2+3x-6 ?
The first derivative of-2x^2+3x-6 is -4x+3