What is (\partial)/(\partial x)(4^x) ?

The answer to (\partial)/(\partial x)(4^x) is ln(2)*2^{2x+1}

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(\partial)/(\partial x)(4^x)

\frac{\partial}{\partial x} (4^{x})

ln (2) \cdot 2^{2 x + 1}

Solution steps

\frac{\partial}{\partial x} (4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4^{x} ln (4)

Simplify

4^{x} ln (4) : ln (2) \cdot 2^{2 x + 1}

= ln (2) \cdot 2^{2 x + 1}

x \to - 2 lim (4 - x^{2})

\frac{sin ( x ) - 1}{sin ( x ) + 4}

\int \frac{1}{f ( x )} d x

\int 1 - cos (2 t) d t

y = x^{3} - 2 x - 2, at x = 1

What is (\partial)/(\partial x)(4^x) ?
The answer to (\partial)/(\partial x)(4^x) is ln(2)*2^{2x+1}