What is (\partial)/(\partial y)(y^3-y) ?

The answer to (\partial)/(\partial y)(y^3-y) is 3y^2-1

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(\partial)/(\partial y)(y^3-y)

\frac{\partial}{\partial y} (y^{3} - y)

3 y^{2} - 1

Solution steps

\frac{\partial}{\partial y} (y^{3} - y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{3}) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (y^{3}) = 3 y^{2}

\frac{\partial}{\partial y} (y) = 1

= 3 y^{2} - 1

f (x) = x^{2} - 8

\frac{s + 1}{s ^{2} ( s + 2 ) ^{3}}

\int 5 t d t

7 sin (\frac{3}{2} t)

y^{^{''}} - y^{^{'}} + 5 y = 0

What is (\partial)/(\partial y)(y^3-y) ?
The answer to (\partial)/(\partial y)(y^3-y) is 3y^2-1