What is inverse oflaplace s/1 ?

The answer to inverse oflaplace s/1 is Undefined

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inverse oflaplace s/1

inverse laplace

\frac{s}{1}

Undefined

Solution steps

L^{- 1} {\frac{s}{1}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {s F (s)} = \frac{d}{d t} f (t) + f (0)

For

\frac{s}{1} : F (s) = \frac{1}{1}

= \frac{d}{d t} (L^{- 1} {\frac{1}{1}}) + L^{- 1} {\frac{1}{1}} (0)

L^{- 1} {\frac{1}{1}} : δ (t)

Evaluate

δ (t)

at point

0 =

Undefined

= Undefined

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\int \frac{1}{x - 70} d x

\int \frac{9 x ^{2} - 8 x + 4}{x ^{3} + 4 x} d x

What is inverse oflaplace s/1 ?
The answer to inverse oflaplace s/1 is Undefined