What is the derivative of-e^{-x}+1/3 ?

The derivative of-e^{-x}+1/3 is e^{-x}

What is the first derivative of-e^{-x}+1/3 ?

The first derivative of-e^{-x}+1/3 is e^{-x}

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\frac{d}{d x} (- e^{- x} + \frac{1}{3})

e^{- x}

Solution steps

\frac{d}{d x} (- e^{- x} + \frac{1}{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (e^{- x}) + \frac{d}{d x} (\frac{1}{3})

\frac{d}{d x} (e^{- x}) = - e^{- x}

\frac{d}{d x} (\frac{1}{3}) = 0

= - (- e^{- x}) + 0

Simplify

= e^{- x}

\int_{2}^{\infty} - 6 x^{- 2} d x

\int \frac{1}{( x - 6 ) x ^{2} - 12 x} d x

\frac{d y}{d x} + (2 x y^{2}) = 0

\int_{1}^{8} x^{- \frac{5}{3}} d x

e^{x} (7 - 5 x + 3 x^{2}), at x = 0

What is the derivative of-e^{-x}+1/3 ?
The derivative of-e^{-x}+1/3 is e^{-x}
What is the first derivative of-e^{-x}+1/3 ?
The first derivative of-e^{-x}+1/3 is e^{-x}